jsjqgbs

说明：  某幼儿园按如下方法依次给A，B，C，D，E五个小孩发糖果。将全部糖果的一半再加二分之一块糖果发给第一个小孩；将剩下糖果的三分之一再加三分之一块糖果发给第二个小孩；将剩下糖果的四分之一再加四分之一块糖果发给第三个小孩；将剩下糖果的五分之一再加五分之一块糖果发给第四个小孩；将最后剩下的11块糖果发给第五个小孩。每个小孩得到的糖果数均为整数。试确定原来共有多少块糖果？每个小孩各得到多少块糖果？ 要求结果的输出格式为 sum＝糖果总数 xa＝A得到的糖果数 xb＝B得到的糖果数 xc＝C得到的糖果数 xd＝D得到的糖果数 xe＝E得到的糖果数
(a kindergarten followed by the following method to the A, B, C, D, E five children made candy. Candy will be half plus half of the candy to the first block of a child; of the remaining one-third of the candy with candy third block to the second child; candy will be left with the fourth quarter to the third block candy child; candy will be left with the fifth block fifth candy to the fourth child; the last remaining 11 candy to the fifth child. Each child received a candy few are integral. The original trial to determine the total number of pieces of candy? Each of the children received how many pieces of candy? The results of the request output format for the total sum = candy xa = A number of the candy xb = B the candy few xc C = the number of candy xd = D The candy few xe E = the number )